thanks in advance! a points MI4 18.10.044 hree identical light bulbs are connect

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thanks in advance!

a points MI4 18.10.044 hree identical light bulbs are connected to two batteries as shown in the diagram above. To start the analysis of this circuit you must write energy conservation (loop) equations. Each equation must involve a round-trip path that begins and ends at the same location. Each segment of the peth should go through a wire, a bulb, ar a battery (not conservation through the air), How many valild energy conservation (loop) equations is it posible to write for this crt? Which of the following equations are valid e nergy conser ation o o equations for this dreu ? Et refers to the electric neid In bulb e ers to the en th of a bulb nla etc Assume that the elect fald in the e necting wires lu all e o g to n neglect. 0 +2.emf-E1L-Ezl-E3L = O It is also necessary to write charge conservation equations (node) equations. Each such equation must relate electron current nowing into a node to electron current lowing out of a node which of the following are valid charge conservation equatieris fer thig f ach bulb is 0 013 m. The rodius of the filament is Se-6 m (5 is very thin). The electron mobility of tungaten is 1 Be-3 (m/s)/(/m). Tungszen has 6e+28 mobile electrons per Each battery has an emf of 1.3 volts. The length of the tungsten filament in e relating these quantities Use any two valid energy conservation equations and one valid charge conservation equation to solve for the following electric fneld magnitudes: Since there are three unknown quantities, we need three equations what is the magnitude of the electric field inside bub 17 what is the magnitude of the electric field inside bulb #27 V/m How many electrons per second enter bulb #17 How many electrons per second enter bulb #2? electrons/s Additional Materials Section 18.10

Explanation / Answer

We can write 3 valid energy conservation ( loop ) equations.

valid energy conservation ( loop ) equations are

+2*emf - E1L - E3L = 0

+2*emf - E1L - E2L = 0

+E2L - E3L = 0

valid charge conservation equation for this circuit is i1 = i2 + i3

using the above equations

E2L = E3L

since current i = neAVd

n = density of charge carriers

A area of cross-section

Vd drift speed

and Vd = mE

m = mobility

E = Electric field

i =  neAVd = neAmE

since E2L = E3L and E2 = E3

i2 = i3

and since i1 = i2 +i3

neAmE1 = neAmE2 + neAmE3

and E1 = E2 + E3 = 2E2 = 2E3

hence +2*emf = E1L + E2L = 3E2L

E3 = V/m

magnitude of electric field inside bulb#1, E1 = 66.67 V/m

magnitude of electric field inside bulb#2, E2 = 33.33 V/m

number of electrons that enter bulb#1 per second = nAmE1 = 3.6 x 1022 /s

number of electrons that enter bulb#2 per second = nAmE2 = 1.8 x 1022 /s

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