nsider the circuit illustrated below. Solve for all the currents through all the

Question

nsider the circuit illustrated below. Solve for all the currents through all the resistors, R1 to R3. (Don't worry about the directions of the currents, only the magnitudes.) Let Vdc-15V, R1-680-ohms, R2-5.6k-ohms, and R3-2.7k-ohms. Show your work for full credit. (You may use PSpice to check your work, but you need to practice working problems by hand for the exams, where you will NOT have PSpice.) R1 R2 R3 Vic- 5. Consider the voltage-divider circuit illhu strated below. Let Vdc-24V and R1-22k-ohms. Select a value for resistor R2 so that the voltage across R2 is 8 volts. Hint: Review the voltage divider equation. R 1 R2

Explanation / Answer

4.

R2 and R3 are in parallel and their combination is given as

R23 = R2 R3 /(R2 + R3) = 5600 x 2700/(5600 + 2700) = 1821.7 ohm

Rtotal = total resistance of the circuit = R1 + R23 = 680 + 1821.7 = 2501.7 ohm

i1 = current in R1 = Vdc/Rtotal =15/2501.7 = 6 mA

V2 = V3 = Vdc - V1 = 15 - (0.006 x 680) = 11 Volts

i2 = V2/R2 = 11/5600 = 2 mA

i3 = i1 - i2 = 6 - 2 = 4 mA

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