elati it in your calculations.) rom est to 8.00% of the speed o light over this

Question

elati it in your calculations.) rom est to 8.00% of the speed o light over this distance trom rest to Be i formed gnore the effects o o charged metallic plates 3.05 cr apart An electric orce accelerates each electron n the bea a) Determine the kinetic energy of the electron as it leaves the electron gun. Blectrons carry this energy to a phosphorescent viewing screen where the microscope's image is formed, making it glow. b) For an electron passing betwcen the plates in the clectron gun, detormine the magnitude of the conatant electric force acting on the clectron (c) Determine the acceleration of the electron n an electron microscope, there is an electron gun that contains t d) Determine the time interval the electron spends between the plates

Explanation / Answer

A]
8% of the speed of light probably won't make that much difference to the mass used to find the KE

mo = 9.1 * 10^-31 kg
v = 0.08 c

m = mo/(sqrt(1 - v^2/c^2)
m = mo/(sqrt( 1 - (.08c / c)^2 )
m = mo / 0.996
m = 9.1*10^-31 / 0.996 = 9.13* 10^-31 kg

Now for the KE
KE = 1/2 m v^2
KE = 1/2 * 9.13 * 10^-31 * 0.08* (3*10^8)^2
KE = 3.29*10^-15 J

C]
d = 3.05 cm = 0.0305m
vi = 0
vf = 0.08 * 3*10^8 = 9.15 * 10^6 m/s
vf^2 = vi^2 + 2*a * d
(9.15 * 10^6)^2 = 0 + 2*a*0.0305
a = 1.37* 10 ^15 m/^2

B]
F = m * a
F = 9.13 * 10^-31 * 1.37 * 10^15
F = 1.25 * 10^-15 N

D]
d = 0.0305 m
vf = 9.15 * 10^6 m/s
vi = 0
t = ?

d = (vf + vi) *t / 2

t = 6.67*10^-9 s

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.