(10%) Problem 2: You have a horizontal grindstone (a disk) that is 85 kg, has a

Question

(10%) Problem 2: You have a horizontal grindstone (a disk) that is 85 kg, has a 0.31 m radius, is turning at 87 rpm (in the positive direction), and you press a steel axe against the edge with a force of 16 N in the radial direction. Otheexpertta.com 50% Part (a) Assuming that the kinetic coefficient of friction between steel and stone is 0.20, calculate the angular acceleration of the grindstone in rad/s2 Grade Summary = 10% 90% Potential sin) | cos() | tan() | | (!)| 7| 8| 9 cotan asinac atan acotan)sinh0 cosh tanh cotanh0) Submissions Attempts remaining: 3 (5% per attempt) detailed view HOME os0 *123 0 5% END 5% s o Radians Submitnteedhackgive up Hints: 1 % deduction per hint. Hints remaining: 3 Feedback: 1% deduction per feedback. 50% Part (b) What is the number of turns, N, that the stone will make before coming to rest?

Explanation / Answer

Here,

angular speed , wi = 87 rpm

wi = 87 * 2pi/60 rad/s

wi = 9.11 rad/s

frictional force , f = 0.20 * 16 = 3.2 N

part a) let the angular acceleration is a

Using second law of motion

0.50 * 85 * 0.31^2 * a = 3.2 * 0.31

solving for a

a = 0.242 rad/s^2

the angular acceleration is 0.242 rad/s^2

b)

let the angle is theta

theta = 9.11^2/(2 * 0.242)

theta = 170 radian = 27.2 turns
the number of turns is 27.2

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