Question 4, chap 111, sect 8. part 1 of 2 10 points A thin hollow cylindrical ro

Question

Question 4, chap 111, sect 8. part 1 of 2 10 points A thin hollow cylindrical rod has length 2.2 m, mass 0.05 kg, and diameter 0.5 cm The thin cylindrical rod is free to rotate about a vertical axis that passes through its center and is perpendicular to the cylinder's axis. Inside the cylinder are two masses of 0.6 kg each, attached to springs of spring constant k and unstretched lengths 0.6 m. The springs have negligible mass. The inside walls of the cylinder are frictionless. Assume the diameter of the cylindrical rod is much smaller than its length. 0.6 kg 2.2m 0.6 kg 0.5 cm 0.05 kg -1.2m-+-when -0 Determine the value of the spring constant k if the masses are located at 0.7 m from the center of the cylinder when the cylindrical rod rotates at 32 rad/s Answer in units of N/m. Question 5, chap 111, sect 8. part 2 of 2 10 points How much work was needed to bring the system from rest to 32 rad/s? Answer in units of J

Explanation / Answer

w = 32 rad/s

on mass. F = k x = m a_c

k x = m w^2 / r

k (0.7 - 0.6) = 0.6 x 32^2 / (0.7)

k = 8777 N/m .....Ans

5. at this time,

total energy = PE + KE

= 2 (8777)(0.1^2)/2 + 2 (0.6) (32 x 0.7)^2 /2 + 2 (0.05) (2.2^2 / 12) (32^2) / 2

= 87.77 + 301 + 20.65

= 409.4 J

Work done = 409.4 J .......Ans

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