In an attempt to pollute the fine sport of curling, the dastardly Swedish team u

Question

In an attempt to pollute the fine sport of curling, the dastardly Swedish team uses a curling stone with a mass of 26.40 kg instead of a regulation stone with mass of 19.17 kg. If the Swedish rock sails down the ice and collides head-on at a speed of 1.127 m/s with a Canadian team stone (at rest). After an elastic collision, the Canadian stone moves off the target. If it is moving across ice with a coefficient of kinetic friction µk = 0.0200, how far does it move before it comes to rest? Express your answer in metres.

Explanation / Answer

for elastic collision,

v2 + v1 = 1.127

v1 = 1.127 - v2

Applying momentum conservation,

(26.40 x 1.127) + 0 = - 26.40 v1 + 19.17 v2

29.7528 = 29.7528 + 26.40 v2 + 19.17 v2

v2 = 1.306 m/s

after that a = -uk g = - 0.02 x 9.81 = - 0.1962 m/s^2

vf^2 - v0^2 = 2 a d

0^2 - 1.306^2 = 2(-0.1962) d

d = 4.35 m

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