Question 3 The total heat lost by the water (the specific heat for water is 4.18

Question

Question 3

The total heat lost by the water (the specific heat for water is 4.186 J/g/K). 100x4.186x(20-10.93) a. = 3796.71 The heat gained by the ice cube after it melts (the specific heat for ice is 2.093J/B/K). 10x2.093x(10.93-0) 228.77 b. c. The heat it took to melt the ice (Hint: it takes 334J of heat energy to melt 1 g ofice). 10x334 = 3340 Inside a calorimeter is 100 g of water at 39.8°C A 10gobject at 50°C is placed inside of a calorimeter. When equilibrium has been reached the new temperature of the water and metal object is 40°C. What type of metal is the object made from? Click here to enter text. 3. Experiment 1: Latent Heat Table 2: Temperature of Frozen Water Over Time Time (s) Temperature (°c) Observation

Explanation / Answer

Heat gained by the water = Heat Lost by the metal

mc[T - To] = Mc'[To - T'']

=> 100[4.1813][40 - 39.8] = 10c'[50 - 40]

=> c' = 0.83626 g/kgK

This is the specific heat capacity of the metal. Use this to determine the metal (which metal has this specific heat capacity).

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