Please only Answers no need of explanation LXAM 3, VERSION 4 (11/21/17) 1. A 75-

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Please only Answers no need of explanation

LXAM 3, VERSION 4 (11/21/17) 1. A 75-W equivalent lig ht bulb provides the same visible light output at 14 W as an incandescent bulb does at 75 W andescent bulbs waste most of the energy as heat light bulbs is the same? A. The incandescent bulb will require a current 5.4 times greater than the LED bulb. B. The incandescent bulb has a resistance 1050 times greater than the LED bulb. C. The incandescent bulb will require a current 28.7 times greater than the LED bulb. D. The LED bulb will require a voltage 1050 times greater than the incandescent bulb. E. The current going into the LED bulb is 14 times greater than the current leaving the LED light bulb. For the as heat). Which of the following is correct if the operaing voltage for both incandescent bulb, that ratio is 75 2. Three identical lamps (A, B, C) are connected to a battery as shown. The switch S is initially open After the swich is closed, what happens to the brightness of lamp C? The resistance of S is negligible A. It increases at first, then slowly decreases as the current is used up by A and B. B. It immediately decreases, but very slightly. C. It stays the same as with S open for all times. D. It immediately drops to zero and stays that way as long as S remains closed E. It immediately increases, but very slightly. C: 3. A battery with internal resistance 0.3 is connected across the endpoints of the circuit in the figure. What is the time constant of the resulting circuit? 200 pF 20.0 pF B. 0.6 us C. 2.0 D. 70 us E. 0.4us 10.0 ALF 200 uF 4. Which of the following is a correct statement about the electric potential in figures I and Il below? A. The electric potential at the midpoint of the upper edges (the lines marked I and II) of the squares is 2kQld in both cases. B. The electric potential at the center of square l is zero. C. The electric potential at the center of square Il equals 4kQld. D. The electric potential at the center of square Il is zero. E. The electric potential at the center of square I is greater than the electric potential at the center of square II.

Explanation / Answer

1. P = V I

ratio = 75/14 =5.4

Ans(A)

2. bulb C is being shortcircuited.

Ans(D)

3. 1/Ceq = 1/(20+20) + 1/10 + 1/(20 +20)

Ceq = 6.67 uF

t = R C = 2 us Ans(C)

4. Ans(E)

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