The pressure wave that travels along the inside of an organ pipe is given in ter

Question

The pressure wave that travels along the inside of an organ pipe is given in terms of distance and time by the following function: p(x, t) (1 atm)cos[ (6 rad/m)x - (4 rad/s)t]. (a) What is the pressure amplitude of the wave? atm (b) What is the wave number of the wave? What is the frequency of the wave? 64 (d) What is the speed of the wave? m/s (e) Whet is the corresponding spatial displacement, s(x, t), from equilibrium for the pressure wave, assuming the maximum displacement is 2.0 cm? (Do not enter units in your expression. Use the following as necessary: x, t. Assume SI units.) s(x, t)-12sin((6)-(4.0)I) | × The spatial displacement stx, t) has an amplitude of 0.02 m and will oscllate with the same wavenumber and angular frequency as the pressure wave. The spatial displacement wave will be 90 degre out of phase with the pressure wave, though, so we should use a sine function, rather than a cosine.

Explanation / Answer

2 cm = 0.02 m (in SI unit)

Therefore the expression for spatial displacement is

s(x,t)=0.02 sin (6 x- 4 t)

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