A Bar Suspended by Two Vertical Strings Part A The figure (Figure 1) shows a mod

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A Bar Suspended by Two Vertical Strings Part A The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m1100 kg and length L 5.00 m is supported by two vertical massless strings. String A is attached at a distance d = 1.80 m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 3500 kg is supported by the crane at a distance = 4.80 m from the left end of the bar. Find TA, the tension in string A. Express your answer in newtons using three significant figures Hints Throughout this problem, positive torque is counterclockwise and use 9.80 m/s2 for the magnitude of the acceleration due to gravity Submit My Answers Give Up Part B Figure 1 of 1 Find TB, the magnitude of the tension in string B Express your answer in newtons using three significant figures Hints an mi Th = Submit My Answers Give Up Part C This question will be shown after you complete previous question(s)

Explanation / Answer

torque equation across left end

Ta*d = m1*g*L/2 + m2*g*x = 100*9.8*5/2 + 3500*9.8*4.8 = 167090

=> Ta = 167090/1.8 = 92827.77 N

torque across string A position point

Tb*d = m1*g*(L/2 - d) + m2*g*(x-d)

=> Tb*1.8 = 100*9.8*(5/2 - 1.8 ) + 3500*9.8*(4.8 - 1.8) = 103586

=> Tb = 57547.77 N

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