thank you!!!! The corroded contacts of a light bulb socket have resistance of 5

Question

thank you!!!!

The corroded contacts of a light bulb socket have resistance of 5 (that's the combined resistance of the two contacts). You screw a light bulb that is rated 100 W at 120 V into the socket. How much power does the light bulb dissipate when 120 V are applied to the socket? Hints: What is the resistance of the light bulb? What is the equivalent resistance of contact and light bulb combined? The current through the light bulb? 2. a) 3. In this circuit, = 12 V, R,-3 , R,-8 , R3-3 , and R4-5 a) Compute the equivalent resistance of the network. b) Compute the current through and voltage across RI c) Determine the voltage across R2 by subtracting 1, from . Compute 12. d) Find the current through and voltage across R3. e) Compute the power dissipated in R3. R4 4. In the circuit on the left, a 6 V battery is connected to points a and b. Compute the power dissipated in the 42 resistor. Hint: You need to first compute several other quantities; let problem 3 guide you 42 40 60 60 45

Explanation / Answer

R across 42 & 60||60||45 = Req = 60 ohm

60 || 40 , Req = 60*40/(60+40) = 24 ohm

So Voltage across 60 ohm = 6 V

Also Voltage across 42 ohm = 6*42/60 = 4.2 V (ans)

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