1. An 8.00g bullet is fired at 220m/s into a 250g wooden block that is initially
ID: 1787277 • Letter: 1
Question
1. An 8.00g bullet is fired at 220m/s into a 250g wooden block that is initially at rest. Thee bullet remains in the block and after the collision the two slide up a 30° incline. Solve for the velocity of the bullet-block after the collision. (ans: 6.82m/s) Determine distance along the incline the bullet-block travel if the incline is frictionless.as: 4.74m) a. b. A 2000kg car moving east at 10.0m/s collides with a 3000kg car moving north. The cars stick together and move as a unit after the collision, at an angle of 40.0° north of east and a speed of 5.22m/s. 2. a. Find the speed of the 3000kg car before the collision. (ans: 5.59m/s)Explanation / Answer
Solution:
1) a) Using law of conservation of momentum
m1v1 + m2 V2 = V ( m1+m2)
=> 0.008 x 220 + 0 = V ( 0.008 + 0.25)
=> V = 6.82 m/s
b) Using Work energy theorem.
=> mgsin30 x d = 0.5 x m (V)^2
=> gsin30 x d = 0.5 V^2
=> 9.8 sin 30 x d = 0.5 x 6.82^2
=> d = 4.746 m
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