1. Two wheels (solid cylinders) are glued to each other and are symmetrically al
ID: 1786949 • Letter: 1
Question
1. Two wheels (solid cylinders) are glued to each other and are symmetrically aligned around a center hole. The small wheel has half the radius of the large wheel and the small wheel has a mass of m, the large wheel a mass of M. A rod is placed in the hole and the wheels can rotate freely around their center. See the figure below for 5 forces acting on the wheels. All of the forces are tangential except for one force that is at 25o to the tangent. a. Find the torques for each force. b. What is the magnitude of the net torque? c. What is the angular acceleration of the system? 2 F 25° / 3 F 0.5 FExplanation / Answer
A) Let the radius of small wheel be r and large wheel be 2r.Let counterclockwise be positive.
Torque of F = - F*2r = - 2Fr
Torque of 3F = 3 Fr
Torque of 0.5F = - 0.5F*2r = - Fr
Torque of 2F = 2F*2r* cos 25 degree = 3.277Fr
B) Net torque = (-2+3-1+3.277) Fr = 3.277 Fr
C) angular acceleration alpha = Torque /moment of inertia
= 3.277Fr/(0.5mr^2 + 0.5M*(2r)^2)
= 3.277F/(0.5mr+ 2 M*r)
Torque of
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