7. + 14.32 points SerCP9 23.P.033 A diverging lens has a focal length of magnitu

Question

7. + 14.32 points SerCP9 23.P.033 A diverging lens has a focal length of magnitude 15.0 cm (a) Locate the images for each of the following object distances. 30.0 cm distance location Select-- cm 15.0 cm distance location -Select cm 7.5 cm distance location --Sele cm ct-- (b) Is the image for the object at distance 30.0 real or virtual? real virtual Is the image for the object at distance 15.0 real or virtual? real virtual Is the image for the object at distance 7.5 real or virtual? real virtual (c) Is the image for the object at distance 30.0 upright or inverted?

Explanation / Answer

f = -15 cm

1/f = 1/p + 1/q

(a) p = 30 cm => q = -10 cm

distance : 10 cm

location: same side as object

(b) p = 15 cm => q = - 7.5 cm

distance : 7.5 cm

location: same side as object

(c) p = 7.5 cm => q = - 5 cm

distance : 5 cm

location: same side as object

(b) virtual for all cases.

(C) image is upright for all cases.

(D) m = - (-10/30) = 0.333

m = - (-7.5/15) = 0.50

m = - (- 5/7.5) = 0.67

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