Light is entering a polarizer or set of polarizers from the left. Determine the

Question

Light is entering a polarizer or set of polarizers from the left. Determine the relative intensity of the light exiting on the right after passing through all of the polarizers. The dashed vertical lines represent the vertical reference. The solid lines represent either the polarization angle of the light or the transmission angle of the polarizer. CW represents clockwise and CCW represents counterclockwise as viewed from the right looking back to the left along the path of the light. Linearly polarized light polarized at an angle 45°CCW from the vertical passes through one polarizer with the transmission axis oriented 45° cCW relative to the vertical and then through a second polarizer with the transmission axis oriented 45° CCW relative to the vertical 6-0 Vertically polarized light passes through a polarizer with the transmission axis oriented 90° relative to the vertical and then through a second polarizer oriented vertically. 0%(vertical) 90° 0%vertical) Vertically polarized light enters from the left and passes first through a polarizer oriented 45°CW from the vertical and the through a polarizer oriented 45° CW. 45°Cw 45 cw 0%(vertical)

Explanation / Answer

I = I0 (cos(theta))^2

theta = 45 - 45 = 0

cos0 = 1

so I = I0

same intensity. ..........Ans

--------------------

for first, theta = 90 - 0 = 90 deg

cos90 = 0

I = 0 ........Ans

---------------------

for first , theta = 45 - 0 = 45 deg

I1 = I0 (cos45)^2 = I0/2

after that theta = 45 - 45 = 0

so I = I1 = I0/2

I = 0.5 I0 or I/I0 = 0.5 .........Ans

Related Questions

Navigate

• Browse (All)
• Browse L
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.