Using your knowledge from your physics one course and the given values, find the
ID: 1786746 • Letter: U
Question
Using your knowledge from your physics one course and the given values, find the change in net force of a person that is standing on the south pole and then moves to the equator, af? Consider gravitational force, buoyant force, and centrifugal force. Which force has the largest impact? (use standard pressure at both locations) Constants K 1.38065 x 10k N-6.02214 x 103 Particles/mol G-6.67428 x 10 Nm/kg -6.37734 x 10° m -6.35522 x 10 m Avogadros Number) Gravitational Constant) Earth's Radius at Equator) Earth's Radius at Poles) (Seconds in a Day, assume 1 day-1 revolution) Mass of Earth) Mass of Person) (Average Density of Person) Air Density at STP) (Pressure at STP) Temperature at STP) Average Temperature at South Polc (Average Temperature at Equator) 8.64000 x 10 s m. 5.98000 x 10* kg m,-9.50000 x 10-kg Pv= 9.85000 x 102 kg/ml p,= 1.204 10 x 10°kgin' P.-1.01325 x 10 Pa T.= 2.73150 x 102 K T- 241350 x 10 K T-3.03150 x 10 K =Gmrma (Force of gravity: r is distance between center of mi and mj Centrifugal force: m is mass being rotated, v is linear velocity of m, r is radius of travel Buoyant force: V is volume displace, p is density of fluid that is displaced, g is acceleration of gravity dependent on F PV = NkT (Ideal gas law: P is pressure, V is volume, N is number of particles, k is Boltmann's constant, and T is temperature in kelvin)Explanation / Answer
for a person on south pole
density of air at south pole = rhos
now, Pa/rhoa*Ta = Pp/rhos*Tp
Pa = Pp
rhos = rhoa*Ta/Tp = 1.20410*273.15/241.35 = 1.36275 kg / m^3
buoyant force, Bs = rhos*mp*G*M/rhop*rp^2 = 1.29881788 N
centrifugal force = 0 N
gravitational force = GM*mp/rp^2 = 938.789088 N
net force = 938.789088 - 1.29881788 = 937.49027012 N
at equator
density of air at equator = rhoe
now, Pa/rhoa*Ta = Pe/rhoe*Te
Pa = Pe
rhoe = rhoa*Ta/Te = 1.20410*273.15/303.15 = 1.08494 kg / m^3
buoyant force, Bs = rhoe*mp*G*M/rhop*re^2 = 1.0268796 N
centrifugal force = mp*(2*pi/8.64*10^4)^2*re = 3.2040215 N
gravitational force = GM*mp/rp^2 = 932.2879844 N
net force = 932.2879844 - 1.0268796 - 3.2040215 = 928.0570833 N
change in force dF = 9.43318682 N
the change in gravitational force has the largest impact
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