Most gasoline engines in today\'s automobiles are belt driven. This means that t

Question

Most gasoline engines in today's automobiles are belt driven. This means that the crankshaft, a rod which rotates and drives the pistons, is timed to the camshaft, the mechanism which actuates the valves, by means of a belt. Starting from rest, assume it takes t = 0.0540 s for a crankshaft with a radius of n = 4.25 cm to reach 1550 rpm. If the belt doesn't stretch or slip, calculate the angular acceleration, 2, of the larger camshaft, which has a radius of r2 8.50 cm, during this time period. Number 2 rad/ s

Explanation / Answer

w0 = 1550 x 2pi rad/ 60s = 162.3 rad/s

Applying wf = w0 + alpha t

162.3 = 0 + alpha(0.0540)

alpha1 = 3005.8 rad/s^2

alpha1 r1 = alpha2 r2

alpha2 = (4.25 / 8.50) (3005.8)

= 1503 rad/s^2

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