Tutt berweeh the plates is then filled with a illl dielectric constant of 7.74.

Question

Tutt berweeh the plates is then filled with a illl dielectric constant of 7.74. What must the magnitude of the charge cacitor plate now be, to produce the same potential difference between the plates as before? 5. A 15-uF air-filled capacitor is connected to a 50-V voltage source and becomes fully charged. The voltage source is then removed and a slab of dielectric that completely fills the space between the plates is inserted. The dielectric has a dielectric constant of 5.0. (a) What is the capacitance of the capacitor after the slab has been inserted? inserted b) What is the potential difference across the plates of the capacitor after the slab has been 2

Explanation / Answer

a] capacitance becomes K =5 times.

new capacitance 5*15 = 75 uF answer

b] Charge is conserved, C2V2 = C1V1

V2 = C1V1/C2 = 15*50/75 = 10 V answer

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