HW 10A My - 201708- nd The Two Item 3 Part A Three forces are applied to a wheel

Question

HW 10A My - 201708- nd The Two Item 3 Part A Three forces are applied to a wheel of radius 0.350 m, as shown in the figure (Figure 1). One force is What is the magnitude of the net torque on the wheel due to these three forces for an axis perpendicular to the wheel and passing through its center? to the rim, one is tangent to it, and the other one makes a 40.0° angle with the radius. of 1 = 0.3 N m 11.9 N Incorrect: Try Again; 4 attempts remaining 40.014.6 N Part B s the direction of the net torque in part (A) into the page 8.50 N out of the page

Explanation / Answer

torque = r x F = r F sin(theta)

net torque = (11.9 x 0.350 x sin0) + (8.50 x 0.350 x sin90) - (14.6 x 0.350 x sin40)

= 0 + 2.975 -3.285

= - 0.310 N m

(A) magnitude = 0.310 N m

(B) into the page

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