this question is broken down, please answer all ** 5 parts *** You are driving i

Question

this question is broken down, please answer all ** 5 parts ***

You are driving in your car at a constant speed. At the very top of a circular hill with a radius of 33 m, you feel 1/5 as heavy as usual What is your actual weight as you go over the top of the hil? (15) mg, upward mg, downward (15) mg, downward (6/5) mg, upward (45) mg, downward Submit Answer Tries 0/1 What is the normal force acting on you as you go over the top of the hill? mg, upward (4/5) mg, upward (6/5) mg, upward (1/5) mg, upward Submit AnswerTries 0/1 What is the total force acting on you as you go over the top of the hill? (15) mg, upward (6/5) mg, upward mg, upward (4/5) mg, downward Submit Answer Tries 0/1

Explanation / Answer

Question 1) since weight (W) = m*g acting downwards and

we feel 1/5 as heavy as usual

Actual weight = (1/5)*mg

Answer) option c)

Question 2) in this the normal force acts opposite to the weight in opposite direction(upward)

N = (1/5)mg

Answer) option d)

Question 3) answer) option E) 0

Reason : in the above situation, all the acting forces are balanced so the total acting force is 0

Question 4) answer ) option d) v^2/r downward

Reason : for the car to move in a circular motion, centripetal acceleration is necessary which is equal to v^2/r ( downward)

Question 5) answer) option B)

Using,

(1/5)*mg = mv^2/r

v^2/r = g/5

v^2 = 9.8*33/5

v = 8 m/s

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