htips:/,\' Homework2-2 Problem 4,67 Resourc0 previous: 90110 | next, Problem 4.6
ID: 1785434 • Letter: H
Question
htips:/,' Homework2-2 Problem 4,67 Resourc0 previous: 90110 | next, Problem 4.67 Part A Your car tire is rotating at 3.2 im revis! when sudcenly you press down hard on the accelerator. After traveling 200 m What was the tire's angular acceleration? Give your answer in (rm radrm s2. Express your answer using two significant figures. the tire's rotation has increased to 5.4 Arm revis)The radius of the tire is 32 m cm alpharm rad)yfrm s2) Submit My Answers Give Up Provide FeedbackC Continue processing math 100%Explanation / Answer
initial angular rotation wi = 3.2 rev/s = 3.2*2pi rad/s = 20.1 rad/s
final angular rotation wf = 5.4 rev/s = 5.4*2pi rad/s = 34 rad/s
linear distance s = 200 m
angular displacement theta = 200/(r) = 200/0.32 = 625 rad
from rotational equation
wf^2 - wi^2 = 2*alpha*theta
34^2 - 20.1^2 = 2*alpha*625
angular accelration alpha = 0.602 rad/s^2 <<<_------------ANSWER
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