1. 0/3 points | Previous Answers SerCP11 4.P.012 Notes + Ask Your Teacher Two fo

Question

1. 0/3 points | Previous Answers SerCP11 4.P.012 Notes + Ask Your Teacher Two forces are applied to a car in an effort to move it, as shown in the figure below. (Let Fi-435 N and F2353 N. Assume up and to the right are in the positive directions.) 10° 30% Fi (a) What is the resultant vector of these two forces? magnitude direction Your response differs from the correct answer by more than 10%. Double check your calculations. N Your response differs from the correct answer by more than 100%.° to the right of the forward direction (b) If the car has a mass of 3,000 kg, what acceleration does it have? Ignore friction m/s Need Help? Read It

Explanation / Answer

(a) F = 435(-sin10i + cos10j) + 353(sin30i + cos30j)

F = 101i + 734j N

magnitude = sqrt(101^2 + 734^2) = 741 N ......Ans

direction = tan^-1(101/734) = 8 deg .........Ans

(B) a = F / m = 741 / 3000

a = 0.247 m/s^2

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