Part A Problem 25.17 For case (a), what is the induced emf? Figure 1) shows a 19
ID: 1785252 • Letter: P
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Part A Problem 25.17 For case (a), what is the induced emf? Figure 1) shows a 19-cm-diameter loop in three different magnetic fields. The loop's resistance is 0.90 Express your answer with the appropriate units Eel Value Units Submit My Answers Give Up Part B For case (a), what is the induced current? Express your answer with the appropriate units. Figure 1 of 1 Value Units Submit My Answers Give Up (a) B increasing at 0.50 T/s (b) B decreasing at 050 T/s (c) B decreasing at 0.50 T/s Part C For case (a), what is the direction of the current? O clockwise O counterclockwise O no current Submit My Answers Give UpExplanation / Answer
Area of loop A = (pi*D2)/4 = 0.025383 m2.
Part A) EMF induced is E = A*(dB/dt) = (0.025383)*0.5 = 0.014176 Volts.
Part B) Induced Current I = E/R = 0.014176/0.9 = 0.01575 Amperes.
Part C) The direction of current is Clockwise.
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