A physics student who needs a magnetic field for a project makes a solenoid coil

Question

A physics student who needs a magnetic field for a project makes a solenoid coil from "magnet wire," which is copper wire coated with a very thin enamel insulation. (The insulation is so thin that you can ignore its thickness.) He chose 29-gauge wire, which is 0.286 mm in diameter, and winds a solenoid that is 50 mm in diameter and 0.40 m long. He then runs a 3.0-A current through the solenoid but is disappointed at how small the magnetic field magnitude is and horrified at how hot the magnet gets after a few minutes. Part A Calculate the magnetic field magnitude. Express your answer with the appropriate units. B

Explanation / Answer

magnetic field inside the solenoid,

B = u0 n I

n = turns per unit length

n = 1/(0.286 x 10^-3)

B = (4pi x 10^-7) (1/0.286x10^-3) (3)

B = 0.0132 T

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