ACCELERATION AND MASS: 2-0.03k s-0.700 kg· lTrial 1.33 1845 6.9924 6264 1 2 3 0

Question

ACCELERATION AND MASS: 2-0.03k s-0.700 kg· lTrial 1.33 1845 6.9924 6264 1 2 3 0 fa i 3395 I 6 5 Plot a vs. 1/m1 m2 with the GS system. Note that t is not reasonable to plot a vs total mass because as the mass increases the acceleration decreases. Hence we plot the inverse Is the plotted data a straight line?--Yes-- What proportlonality exists between a and total maes? The slope of your graph isaa6a3 The theoretical slope s the constant force you applied. Its value? % difference Write down the complete mathematical expression relating a F and total mass.

Explanation / Answer

The slope of the graph m = (0.72-0.64)/(2.74-2.41)

m = 0.2424

Theoritical slope : F = (m1+m2)a

Put values to get answer.

The mathematical relation that relating F,m and a is:

F = ma ( Newtown second law)

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