1. + -I3 points YFWA13 21 P.058. My Notes Ask Your Tea A disk with uniform surfa

Question

1. + -I3 points YFWA13 21 P.058. My Notes Ask Your Tea A disk with uniform surface charge density = 8.90 c m2 is oriented as shown in the diagram below. The field at a distance·from the center of dis of ad usn and aong its axis is given by E.(1- ) wherec,.sas-1012 carcN. 1 where .-8.85 × 10-12 C2/(N-m2) is the permittivity of free space. Zeo Vy2 2 ), P (0.y (a) If the radius of the disc is 0.420 m, what is the electric field at a location P whose coordinates are (0, 0.140 m)? magnitude direction N/C -Select- (b) What is the magnitude of the electric field at a location very close to the disc? (Assume y.) N/C

Explanation / Answer

the equation for electric field is

E = sigma/ 2 eo ( 1- y/ sqrt y^2 + r^2)

=-8.9 * 10^-6 C/m^2/ 2 (8.85 * 10^-12) ( 1- 0.140/ sqrt ( 0.140)^2 + (0.420)^2

= -3.43 * 10^5 N/C

along the y axis

(b)

when r>>y

we can neglect y term in the denominator

E = sigma/ 2 eo ( 1- y/ r)

=-8.9 * 10^-6 C/m^2/ 2 (8.85 * 10^-12) ( 1- 0.140/ (0.420)

= -3.33 * 10^5 N/C

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