You are studying a population of parrots. The parrots are generally either whist

Question

You are studying a population of parrots. The parrots are generally either whistlers, squawkers or are able to do both with this trait controlled by a gene at a single locus. Parrots with WW genotype are whistlers. Those with ww are squawkers and those with Ww are able to make both sounds. You assume that the parrots are in Hardy-Weinberg equilibrium. You take a survey of the parrots and find the following numbers: whistlers: 4900 squawkers: 900 both: 4200

Calculate the genotype and allelic frequencies in this population of parrots.

Explanation / Answer

Answer:

The frequency of squawkers (ww)= q^2 = 900/ 10000 = 0.09

The frequency of squawkers allele(w) = q = 0.3

The frequency of squawkers (WW)= p^2 =4900/ 10000 = 0.49

The frequency of squawkers allele(W) = p = 0.7

The frequency of parrots make both sounds (Ww)= 2pq =2 * 0.7 * 0.3 = 0.42

Hardy-Weinberg equilibrium, p^2 + 2pq + q^2 = 1

0.49 + 0.42 + 0.09 = 1

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