A simple Mary go round has a rotational inertia of 800 kg meters squared and a r

Question

A simple Mary go round has a rotational inertia of 800 kg meters squared and a radius of 2 m a child with a mass of 40 kg sits near the edge of the merry-go-round what is the total rotational inertia of the merry-go-round and the child about the axis of the merry-go-round A simple Mary go round has a rotational inertia of 800 kg meters squared and a radius of 2 m a child with a mass of 40 kg sits near the edge of the merry-go-round what is the total rotational inertia of the merry-go-round and the child about the axis of the merry-go-round

Explanation / Answer

here,

mass of Merry go round , M = 800 kg

mass of child , m = 40 kg

radius ,r = 2 m

the total rotational inertia of the merry-go-round and the child about the axis of the merry-go-round , I = 0.5 * M * r^2 + m * r^2

I = 0.5 * 800 * 2^2 + 40 * 2^2 kg.m^2

I = 1760 kg.m^2

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.