PHHY 213 University Physiesl October 19-21, 2017 Prof. L. P. Johnson Part II. So
ID: 1784130 • Letter: P
Question
Explanation / Answer
a)
Inner sphere has charge = +q
Due to induction charge on inner surface of the shell = - q
Charge on outer surface on the shell = -q
Charge on Inner surface is balanced by charge on the sphere, hence charge on the outer surface = - q
b)
Use Gauss’s law,
E.da = qiclosed /0
E = qiclosed /40r2
E = 0/40r2
E = 0
c)
Use Gauss’s law,
E.da = qiclosed /0
E = qiclosed /40r2
E = +q/40r2
d)
Use Gauss’s law,
E.da = qiclosed /0
E = qiclosed /40r2
E = (+q + -q)/40r2
E = 0
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