Figure (a) Rod Ris now moved away from Yand r Spheres Fand one another as in Fig

Question

Figure (a) Rod Ris now moved away from Yand r Spheres Fand one another as in Figure (b) are then moved away from Figure (b) What are the final charge states of Yand ? A) ris negative and Fis positive. B) Fis positive and Fis neutral. C) Both Yand Fare neutral. D) Both X and Yare negative. E) is neutral and l'is positive. 12) A very long wire carries a uniform linear charge density of 7.0 nC/m. What is the 12 electric field strength 16.0 m from the center of the wire at a point on the wire's perpendicular bisector? (D = 8.85 × 10-12 C 2/N·m2) A) 7.9 N/C B) 3.9 N/C C) 0.49 N/C D) 0.031 NC

Explanation / Answer

1st)

C) Both X and Y are neutral

In the presence of therod R, due to attraction , all the negative charges move to X and positive charges are repelled and contained in Y. If X and Y were separated before removing R, the X would be negatively charged and Y would be positively charged.

As R is removed, the charges in X and Y distribute again and hence they become neutral.

12)

E is given by:

E = lambda/(2pi*epsilon0*r)

Given: lambda = 7nC/m = 7*10^-9 C/m

epsilon0 = 8.85*10^-12

r = 16m

Plugging in the values, we get:

E = 7.9 N/C (option A)

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