You are in an airplane circling an airport at a speed of 500 km/hour on a circul

Question

You are in an airplane circling an airport at a speed of 500 km/hour on a circular path of radius 2 km. A cup, of mass 0.1 kg, is dropped on the floor of the airplane. It is released from rest at a perpendicular distance of 1.5 m from the floor. (That is to say, the shortest distance from the cup to a spot on the floor is 1.5 m.) What is its speed, relative to the airplane, when it hits the floor? (That is, what is the magnitude of the velocity of the cup, measured in the reference frame of the airplane?) Include a clear sketch indicating the floor of the airplane, the position of the cup when it is released, the position of the cup when it hits the floor and the angle at which the airplane is banked.

Explanation / Answer

v= sqrt (2*g*h)

= sqrt (2*9.8*1.5)

= 5.42 m/s

it doesn't matter, whether the object is inside or outside the airplane, speed will be the same.

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