A mechanic pushes a 3.10 x 103-kg car from rest to a speed of v, doing 5,190 3 o

Question

A mechanic pushes a 3.10 x 103-kg car from rest to a speed of v, doing 5,190 3 of work in the process. During this time, the car moves 20.0 m. Neglecting friction between car and road, find v and the horizontal force exerted on the car. (a) the speed v m/s (b) the horizontal force exerted on the car (Enter the magnitude.) A 69-kg base runner begins his slide into second base when he is moving at a speed of 3.7 m/s. The coefficient of friction between his clothes and Earth is 0.70. He slides so that his speed is zero just as he reaches the base (a) How much mechanical energy is lost due to friction acting on the runne? (b) How far does he slide?

Explanation / Answer

Applying work - energy theorem,

Work done = change in KE

5190 = 3.10 x 10^3 (v^2 - 0)/ 2

v = 1.83 m/s

(b) W = F.d

5190 = F (20)

F = 259.5 N

  

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