b) Also convert the answer from seconds to hours. Step 2 The equation GMs gives

Question

b) Also convert the answer from seconds to hours.

Step 2 The equation GMs gives Kepler's third law in a form suitable for objects orbiting the Sun. To modify it to a form suitable for objects in the Earth's orbit, we replace the mass of the Sun with the mass of the Earth to obtain the following expression for the period T of the satellite, where G is the constant of universal gravitation, ME is the mass of the Earth, and r is the radius of the satellite's orbit that we found above GME Solving for the period of the satellite, we have GME 4T2 9.33 x106 m 6.67 × 10-11 N·m2/kg2V1 kg·m/s2)(5.98x 1024 kg) 2wa2)( 1 kg·m/s2 Your response differs significantly from the correct answer, Rework vour solution from the beginning and check

Explanation / Answer

Correct answer would be 2.49 hours

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