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Bookmarks People Window Help e Can I Get Help With This Plea; e Chegg Study I Guided Solutio. x iscms/mod/ibis/view.php?id-4444682 Jump to... on 6 of 14 Ma Sapling Learning A spring with force constant 313 N/m is in a compressed state, 0.423 m shorter than its relaxed length. In this condition, the spring serves a vital purpose in a device for dete impending earthquakes. A curious ysicist releases the spring and, moreover, stretches it until it is 0.111 m longer than its relaxed length. at renders the earthquake detector useless, and it fails to warn of a very strong earthquake that subsequently shatters all the lawn sculptures in the area-fortunately with no other damage or injury Although some might consider this to be beneficial, the physicist's boss does not. She had some extremely unattractive plaster gnomes around her yard and loved them dearly. So she imposes a punishment on the physicist and requires him to calculate the change of elastic potential energy that he caused by his medding. What does he find? Number Previous @ove up & View Solution echeck AnswerNext Exit- us careers privacy policy terens of use contact us help

Explanation / Answer

change in elastic potential energy

delta E = 1/2 k x22 - 1/2 k x12

= 1/2 k (x22 - x12)

= 1/2 * 313 * ( 0.1112 - 0.4232)

= -26.1 J

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