iPad 12:16 AM 17% D a session.masteringphysics.com co + D MasteringPhysics: Ch 1
ID: 1782977 • Letter: I
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iPad 12:16 AM 17% D a session.masteringphysics.com co + D MasteringPhysics: Ch 10 HW iPad11:04 PM 4 Session-masteringphysics.com 19..· ! Ch Problem 10.88 MasteringPhysics 10 of 13 Problem 10.88 The V6 engine in a 2014 Chevrolet Silverado 1500 pickup truck is reported to produce a maximum power of 285 hp at 5300 rpm and a maximum torque of 305 ft lb at 3900 rpm Part A Calculate the torque (in ft lb) at 5300 rpm Express your answer using three significant figures. = 283 ft·lb Submit Give UP Correct Part B Is your answer smaller than the specified maximum value? smaller greaterExplanation / Answer
part C:
Power P = Torque * Angular velocity
given Power P = 285 hp
1 hp = horse power = 746 Watts
angular velcoity W = 5300 rpm = 5300* 2pi/60
W = 554.73 rad/s
Torque T = P/W
T = 285* 746/(554.73)
T = 383.26 Nm
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Part D :
Power P = T W
P = 383.26 * 3900 * 2pi/60
P = 156446.732 Watts
P = 156446.732/746
P = 210 Hp
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