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iPad 12:16 AM 17% D a session.masteringphysics.com co + D MasteringPhysics: Ch 1

ID: 1782977 • Letter: I

Question

iPad 12:16 AM 17% D a session.masteringphysics.com co + D MasteringPhysics: Ch 10 HW iPad11:04 PM 4 Session-masteringphysics.com 19..· ! Ch Problem 10.88 MasteringPhysics 10 of 13 Problem 10.88 The V6 engine in a 2014 Chevrolet Silverado 1500 pickup truck is reported to produce a maximum power of 285 hp at 5300 rpm and a maximum torque of 305 ft lb at 3900 rpm Part A Calculate the torque (in ft lb) at 5300 rpm Express your answer using three significant figures. = 283 ft·lb Submit Give UP Correct Part B Is your answer smaller than the specified maximum value? smaller greater

Explanation / Answer


part C:


Power P = Torque * Angular velocity

given Power P = 285 hp

1 hp = horse power = 746 Watts

angular velcoity W = 5300 rpm   = 5300* 2pi/60

W = 554.73 rad/s

Torque T = P/W

T = 285* 746/(554.73)

T = 383.26 Nm

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Part D :

Power P = T W

P = 383.26 * 3900 * 2pi/60

P = 156446.732 Watts

P = 156446.732/746

P = 210 Hp

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