A 4.50-mol sample of ideal gas with molar specific heat CV = 52R is initially at

Question

A 4.50-mol sample of ideal gas with molar specific heat CV = 52R is initially at 275 K and 101 kPa pressure. 1.75 kJ of heat are added to the gas. Determine the final temperature if heat is added to the gas isothermally. Determine the the work done by the gas if heat is added to the gas isothermally. Determine the final temperature if heat is added to the gas at constant volume. Determine the the work done by the gas if heat is added to the gas at constant volume. Determine the final temperature if heat is added to the gas at constant pressure. Determine the the work done by the gas if heat is added to the gas at constant pressure.

Explanation / Answer

part A

as iso thermally

delta T =0

Tf= Ti = 275K

Part B

work done by gas + change in internal energy = heat added

as delta U =0

hence work done

= 1.75 kJ

Part C

at constant volume Cv= 5/ 2R

delta U = nCv*delta T = 1.75kJ

n=4.5

we get delta T= 18.701

Tf = 293.701 K

Part D

at constant V work done is 0

Part E

Cp = Cv +R

= 7R/2

nCp delta T = 1.75kJ

delta T = 13.36

we get

Tf= 288.36 K

Part F

work done = nCp*delta T - nCv *delta T

we get

= n*R*delta T

=193.16 J

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.