C. The gymnast then tucks her legs up so they are touching the bar along with he

Question

C. The gymnast then tucks her legs up so they are touching the bar along with her hands. What is, roughly, the ratio of the moment of inertia of her body around the bar with her legs tucked up to the moment of inertia of her body around the bar with her legs outstretched. Assume the distance from the bar to the farthest point on her body from the bar is 1.25 m with her legs tucked.(3 pt) Model the gymnast as a bar rotating around one end in both cases. Outstretched the bar's length is 2.5 m, with her feet tucked the bar's length is 1.25 m D. Will her immediate angular speed go up, go down, or remain the same when she tucks her legs up compared to when her legs were outstretched? Why? (2 pt)

Explanation / Answer

We know moment of inertia of rod about one end =(1/3)*M*L*L

So their ratio will be equal to =(L1/L2)*(L1/L2)=4:1

Since moment of inertia will decrease so angular speed will increase to conserve momentum

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