The crystalline lens of the human eye is a double-convex lens made of material h

Question

The crystalline lens of the human eye is a double-convex lens made of material having an index of refraction of 1.44 (although this varies). Its focal length in air is about 8.00 mm , which also varies. We shall assume that the radii of curvature of its two surfaces have the same magnitude.
(Note: The results obtained in the parts A, B and C are not strictly accurate, because the lens is embedded in fluids having refractive indexes different from that of air.)

Part A

Find the radii of curvature of this lens.

Part B

If an object 15.0 cm tall is placed 27.0 cm from the eye lens, where would the lens focus it?

Part C

How tall would the image be?

Part D

Is this image real or virtual?

Part E

Is it erect or inverted?

Explanation / Answer

a) 1/f = (n - 1) * [1/R2 - 1/R1]

1 / 8* 10-3 = (1.44 - 1) * 2 / R

R = 2 * 0.44 * 8 * 10-3

radii of curvature R = 7.04 * 10-3 m = 7.04 mm

b) From lens equation 1/f = 1/p + 1/q

1/q = 1/(8 * 10-3) - 1/(27 * 10-2)

q = 8.24 mm = 0.824 cm

c) h' = -0.824 * 15 / 27 = -0.458 cm

d) image is real

e) image is inverted

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