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Safari File Edit View History Bookmarks Window Help 0 webassign.net eW 11- Mechanies My Notes Ask Your Teacher ·04 poles l previous Answers CJ107 P024. Interactive Solution 7.24 offers help in modeling this problem. A 0.014 kg bulet is fired straight up at a falling wooden block that has a mass of 4.0 kg. The bullet has a speed of 700 m/s when it strikes the block. The block originally was dropped from rest from the top of a building and had been falling for a t when the collision with the bullet occured. As a result of the collision, the block (with the bullet in it) reverses direction, rises, and comes to a momentary halt at the top of the building. Find the time t. 700 Additional Materialts Section 72 My Notes Ask Your A1055 vin stopped at a traffic light, s in neutral, inal velocity of the car is 04 m/s, what is the mass of the car s hit directly in the rear by another car. Assume that the the brakes are not being applied, and the collision is elastic. If the final velocity of the van is 4 m/s, and the and what was its initial velecity? m/s 0 838

Explanation / Answer

let m = 0.014 kg

M = 4 kg

v = 700 m/s

let h is the distance travelled by the block from the top of the building.

h = (1/2)*g*t^2

==> t = sqrt(2*h/g)

velocity of the block when the bullet hits the block = -g*t

let V is the velocity of bullet-block system after the bullet is penetrated into the block.

so, h = V^2/(2*g)

V = sqrt(2*g*h)

Apply conservation of momentum,

m*v + M*(-g*t) = (m + M)*V

0.014*700 + 4*(-9.8*sqrt(2*h/9.8)) = (0.014 + 4)*sqrt(2*9.8*h)

==> h = 0.0763 m

so, t = sqrt(2*h/g)

= sqrt(2*0.0763/9.8)

= 0.125 s <<<<<<<<-------------------Answer

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