At t = t of t (a) At what time is the angular velocity of the motor shaft zero?

Question

At t = t of t (a) At what time is the angular velocity of the motor shaft zero? 2.04 (b) Calculate the angular acceleration at the instant that the motor shaft has zero angular velocity 216.002 6002xrad/s2 (c) How many revolutions does the motor shaft turn through between the time when the current is reversed and the instant when the angular velocity is zero? rev (d) How fast was the motor shaft rotating at t0, when the current was reversed? rad/s (e) Calculate the average angular velocity for the time period from t = 0 to the time calculated in part (a) 130.07 X rad/s

Explanation / Answer

A)
= d/dt = 260 – 38*t - 4.35t² = 0

t = 4.5 s

B)
= d/dt = -38 – 8.7*t
= -38 – 8.7*(4.5)
= -77.15 rad/s²

C)
= 260(4.5) - (19)(4.5)² - (1.45)(4.5)³
= 653.1 rad

(653.1 rad)(rev / 2 rad) = 103.94 rev

E)
average = /t
/t = 653.1 rad / 4.5 s
/t = 145.1 rad/s

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