The following data gives stopping potential Vo versus wavelength for photoelectr

Question

The following data gives stopping potential Vo versus wavelength for photoelectrons produced from a metal surface. (Be sure to include the correct units and use three significant figures.) Table 1 Vo (nm) (volts) 50 100 9,33 150 5.19 200 3.15 2501.86 300 1.05 21.4 Use an analysis similar to that used in the inlab procedure to determine the work function (in ev) for this surface. (Use 1 ev -1.602 x 10-19j, e- 1.602 x 10-19 c, c2.998 x 108 m/s, and h = 6.626X10-34 , s = 4.136 × 10-15 ev . s as necessary.)

Explanation / Answer

work function = hc/ - eVo

1) work function = ((6.626 x 10-34 x 2.998 x 108/50 x 10-9) - (1.602 x 10-19 x 21.4))/(1.602 x 10-19) eV

= 4 eV

2) work function = ((6.626 x 10-34 x 2.998 x 108/100 x 10-9) - (1.602 x 10-19 x 9.33))/(1.602 x 10-19) eV

= 3.07 eV

3) work function = ((6.626 x 10-34 x 2.998 x 108/150 x 10-9) - (1.602 x 10-19 x 5.19))/(1.602 x 10-19) eV

= 3.076 eV

4)  work function = ((6.626 x 10-34 x 2.998 x 108/200 x 10-9) - (1.602 x 10-19 x 3.15))/(1.602 x 10-19) eV

= 3.05 eV

5)  work function = ((6.626 x 10-34 x 2.998 x 108/250 x 10-9) - (1.602 x 10-19 x 1.86))/(1.602 x 10-19) eV

= 3.1 eV

6)  work function = ((6.626 x 10-34 x 2.998 x 108/300 x 10-9) - (1.602 x 10-19 x 1.05))/(1.602 x 10-19) eV

= 3.083 eV

=> work function is around 3.07 eV

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