xercise 7.26 Part A A 2.65 kg block on a horizontal floor is attached to a horiz

Question

xercise 7.26 Part A A 2.65 kg block on a horizontal floor is attached to a horizontal spring that is initially compressed 0.0400 m. The spring has force constant 820 N/m What is the speed of the block when it has moved a distance of 0.0140 m from its initial position? (A this point the spring is compressed 0.0260 m.) Express your answer with the appropriate units. The and the block is 0.45. The block and spring are released from rest and the block slides along the floor. nt of kinetic friction between the floor ? 0.561 m Incorrect; Try Again; 2 attempts remaining Proxide Fectback Continue

Explanation / Answer

energy is always conserved

intial spring energy = final spring energy + kinetic energy of block + work done by friction

0.5 x 820 x 0.042 = 0.5 x 820 x 0.0262 + 0.5 x 2.65 x V2 + 2.65 x 9.8 x 0.45 x 0.014

V= 0.403 m/s

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