A) The resistance offered by circuit 1 is twice the resistance offered by circui

Question

A) The resistance offered by circuit 1 is twice the resistance offered by circuit 2.
B) The resistance offered by circuit 1 is larger than the resistance offered by circuit 2, but not twice the size
C) The resistance offered by circuit 1 is the same as the resistance offered by circuit 2
D) The resistance offered by circuit 1 is half as large as the resistance offered by circuit 2
E) The resistance offered by circuit 1 is smaller than the resistance offered by circuit 2, but not half the size

25) Compare the size of the current through Bulb C with the size of the current through Bulb A.

A) The current through bulb C is twice the size of the current through bulb A.
B) The current through bulb C is larger than the current through bulb A, but not twice the size
C) The current through bulb C is the same as the current through bulb A.
D) The current through bulb C is half the size of the current through bulb A.
E) The current through bulb C is smaller than the current through bulb A, but not half the size.

26) Compare the voltage across bulb C, with the voltage across A.
A) The voltage across bulb C is twice the size of the voltage across bulb A.
B) The voltage across bulb C is larger than the voltage across bulb A, but not twice as large
C) The voltage across bulb C is the same as the voltage across bulb A.
D) The voltage across bulb C is half the size of the voltage across bulb A.
E) The voltage across bulb C is smaller than the voltage across bulb A, but not half the size

27) Compare the brightness of bulb C with the brightness of bulb A.
A) Bulb C is brighter than bulb A
B) Bulb C has the same brightness as bulb A
C) Bulb C is dimmer than bulb A

Explanation / Answer

assuming the three light bulbs have got the same individual resistance,

Req(1) = R + R = 2R

Req(2) = R

The resistance of circuit 1 is 2 times that of circuit 2

24)correct Ans is:

A) The resistance offered by circuit 1 is twice the resistance offered by circuit 2.

25)D) The current through bulb C is half the size of the current through bulb A.

I = V/R

I1 = V/2R ; I2 = V/R

I2 = 2 I1

So the current flowing through the resistors of circuit 1 is half of circuit 2.

26)D) The voltage across bulb C is half the size of the voltage across bulb A.

Vc = I x Rc

Va = Vb

27)C) Bulb C is dimmer than bulb A

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