7. +-6 points SerCP11 6.P.048 My Notes Ask Your Teacher A billiard ball rolling

Question

7. +-6 points SerCP11 6.P.048 My Notes Ask Your Teacher A billiard ball rolling across a table at 1.45 m/s makes a head-on elastic collision with an identical ball. Find the speed of each ball after the collision when each of the following occurs. (a) The second ball is initially at rest. first ball second ball m/s m/s (b) The second ball is moving toward the first at a speed of 1.15 m/s. first ball second ball m/s m/s (c) The second ball is moving away from the first at a speed of 1.10 m/s. first ball second ball m/s m/s Need Help? Resd t

Explanation / Answer

by the law of momentum conservation

m1u1+m2u2=m1v1+m2v2

u1+u2=v1+v2

1.45+0=v1+v2 eq (1).

for elastic collision

v1-v2=u2-u1

v1-v2=0-1.45 eq(2)

br eq(1) and (2)

2v1=0

v1=0

v2=1.45

1st ball=0m/s

2nd ball=1.45m/s

B)1.45-1.15=v1+v2

v1+v2=0.3 eq(1)

v1-v2=-1.15-1.45

v1-v2=-2.6 eq(2)

by (1) and (2)

v1=1.45m/s

v2=1.15m/s

1st ball=1.45m/s

2nd ball=1.15m/s

C)1.45+1.10=v1+v2

v1+v2=2.55 eqw(1)

v1-v2=1.45-1.10

v1-v2=0.35 eq(2)

by (1) and(2)

v1=1.1m/s

v2=-1.45m/s

1st ball=1.1m/s

and 2nd ball=-1.45m/s.

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