The 2017 Dodge Viper GTS with its driver weighs 3580 pounds and can accelerate f

Question

The 2017 Dodge Viper GTS with its driver weighs 3580 pounds and can accelerate from zero to 60.0 mph in 3.30 seconds. If 70.0% of the work done by the engine becomes the kinetic energy of the car, find the average power output of the engine during this time. The 2017 Dodge Viper GTS with its driver weighs 3580 pounds and can accelerate from zero to 60.0 mph in 3.30 seconds. If 70.0% of the work done by the engine becomes the kinetic energy of the car, find the average power output of the engine during this time.

Explanation / Answer

Given : m = 3580 lb = 1625.32 kg ; v = 60 mph = 26.82 m/s ; t = 3.30 s

KE = 0.70 W

Solution:

70% of the work done by engine becomes the kinetic energy ,

i.e. 0.70 W = ME = (1/2)mv2

0.70W = (1/2)(1625.32)(26.82)2 = 584556.41 J

W = 584556.41 J/ 0.70 = 835.08 kJ

Power output can be given as

P = W/t = 835.08 J/ 3.3 s = 253.05 kW

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