Tipler6 19.P.070 1 2 3 4 Calvin Cliffs Nuclear Power Plant, located on the Hobbe

Question

Tipler6 19.P.070 1 2 3 4 Calvin Cliffs Nuclear Power Plant, located on the Hobbes River, generates 1.00 GW of power. In this plant, liquid sodium circulates between the reactor core and a heat exchanger located in the superheated steam that drives the turbine. Heat is absorbed by the liquid sodium in the core, and released by the liquid sodium (and into the superheated steam) in the heat exchanger. The temperature of the superheated steam is 538 K. Heat is released into the river, and the water in the river flows by at a temperature of 26 C 1) (a) What is the highest efficiency that this plant can have? Submit You currently have O submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question.

Explanation / Answer

We know that maximum efficiency is given by Carnot efficiency

Carnot efficiency = 1 - Tc/Th = 1 - 299.15/538 = 0.444 or 44.4% Highest Efficiency (Answer 1a)

[Tc= 26°C = 299.15K, Th= 538K]

Carnot efficiency = (Qin - Qout)/Qin = 0.444

Thus, 1GW/Qin = 0.444 This imples Qin = 1GW/0.444 = 2.252 GW

[Qin - Qout = 1GW;]

Now, Qin - Qout = 1GW; Thus, 2.252 GW - Qout = 1GW This implies Qout = 2.252 GW - 1GW =1.252 GW Ans2b

As calculated in part 2(b), Qin = 2.252 GW Heat released by core Answer 3c

Heat transfered to river water = Qout = 1.252 GW = mCwdt [where, m = mass flow rate; Cw = specific heat of water = 4.179 KJ/KgK; dt = 0.5°C or K]

Thus, m = 1.252 GW / (Cwdt) = 1.252 GW / (4.179 KJ/KgK * 0.5 K) = 1.252x109Js-1 / (4.179 * 103 J/KgK * 0.5 K)

Thus, m = 599186.4 kg/s = 599186.4 L/s Answer 4d [For water, 1L = 1Kg]

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.