dep:16179200 Search.. View Favontes Tools Help The rotating loop in an AC genera

Question

dep:16179200 Search.. View Favontes Tools Help The rotating loop in an AC generator is a square 10.0 cm on a side. It is rotated at 90.0 Hz in a uniform field of 0.800 T. Calculate the following quantities as functions of time is in seconds. (a) the flux through the loop (b) the emf induced in the loop (c) the current induced in the loop for a loop resistance of 2.00 (d) the power delivered to the loop (e) the torque that must be exerted to rotate the loop Need Help?Re Progress Practice Another Versien

Explanation / Answer

a) Flux through loop = B A cos w t

= 0.8 * 0.12 *cos (2pi * 90) t

= 8.0 cos (565.49 t) mT.m2

b) emf induced in the loop E = -dphi/dt

= 8 * 10-3 * 565.49 * sin (565.49 t)

= [ 4.52 * sin (565.49 t) ] V

c) current induced in the loop I = E / R

= 4.52 * sin (565.49 t) / 2

= [ 2.26 * sin (565.49 t) ] A

d) power delivered = I2 * R

= [ 2.26 * sin (565.49 t) ]2 * 2.00

= 10.2 * sin2 (565.49 t) W

e) torque = B I A sin wt = 0.8 * 0.12 *  2.26 * sin2 (565.49 t)

= 18 * sin2(565.49 t) mN.m

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