iPad 4:19 PM ) 34% . session.masteringphysics.com c + blac (15) kineti.... (16)
ID: 1779818 • Letter: I
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iPad 4:19 PM ) 34% . session.masteringphysics.com c + blac (15) kineti.... (16) Conse 8:44 PM 6.. Microsoft...Course Ho...Masteri.. 10.0 Kg Mi.. HW1018 Exercise 7.35 previous 7of8 Ineat /r12_br®. where r is the spac ng between atoms and a and The potential energy of two atoms in a dat nic molecule is approximated by U r) positive constants are Part A Find the component of force along the line connecting the two atoms, F.(r),on one atom as a function of Express your answer in terms of the variables a, 6, andr 12a My Answers Give Up Correct Part B Find the equlibrium distance between the two atoms Express your answer in terms of the variables a and b My Answees Give Up Correct Part c s this equlibrium stable? yes Mr Ansett Give Up Correct Part D Suppose the distance between to two atoms is equal tothe equibrium dstance folnd part A what mnimrn energy must be added to the molecule to dissociate it-that is, to separate the two atoms to an infinite distance apart? This is caled the dissociation energy of the molecule. Express your answer in terms of the variables a and b hly Answers teUp Part EExplanation / Answer
As given parts upto c are solved.
Other parts are determined below with the help of given parts.
d)
energy added = Ufinal - Uinitial = -a (2 a/b)^(-2) + b ( 2 a/b)^(-1)
= -a b^2/( 4 a^2) + b^2/2a
= -b^2/(4 a) + b^2/(2a)
= b^2/4a
e)
so r^6 = 2a/b and E = b^2/4a
so b = 2 a/r^6
1.54E-18 = ( 2*a/1.13E-10^6)^2/(4*a)
a=6.68E-138
b = 2*6.68E-138/(1.13E-10^6)= 6.42E-78
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