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A parallel plate capacitor with plate separation d is connected to a battery. Th

ID: 1779785 • Letter: A

Question

A parallel plate capacitor with plate separation d is connected to a battery. The capacitor is fully charged to Q Coulombs and a voltage of V. (C is the capacitance and U is the stored energy.) Answer the following questions regarding the capacitor charged by a battery. For each statement below, select True or False.

After being disconnected from the battery, increasing d increases V. A: True B: False

With the capacitor connected to the battery, inserting a dielectric with will increase U. A: True B: False

After being disconnected from the battery, increasing d increases U. A: True B: False

After being disconnected from the battery, decreasing d increases C. A: True B: False

With the capacitor connected to the battery, inserting a dielectric with will increase C. A: True B: False

After being disconnected from the battery, inserting a dielectric with will decrease V. A: True B: False

Explanation / Answer

After being disconnected from the battery, increasing d increases V:

True

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With the capacitor connected to the battery, inserting a dielectric with will increase U:

True. U = CV²/2 so energy will increase to U because capacitance will increase to C (V remains constant).

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After being disconnected from the battery, increasing d increases U :

True. U = Q²/2C and C = A/d. C increases linearly with decrease in d, and U decreases linearly with increase in C, therefore U increases linearly with increase in d.

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After being disconnected from the battery, decreasing d increases C :

True. using the above relation.

________________________

With the capacitor connected to the battery, inserting a dielectric with will increase C:

True. Capacitance will increase to C.

_________________________

After being disconnected from the battery, inserting a dielectric with will decrease V:

True. V will decrease. The dielectric sets up a back EMF which partially cancels V.

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