Just before hitting the boards of a hockey rink, a puck is sliding along the ice

Question

Just before hitting the boards of a hockey rink, a puck is sliding along the ice at a constant velocity. As shown in the figure, the components of this velocity are 3 m/s in the direction perpendicular to the boards and 4 m/s parallel to the boards. Immediately after bouncing off the boards, the puck's velocity component parallel to the boards is unchanged at 4 m/s, and its velocity component perpendicular to the boards is 1 m/s in case A, 2 m/s in case B, and 3 m/s in case C A B C 4 m/s 3 m/s (a) Without doing any calculations, rank the three cases based on the magnitude of the impulse the puck experienced because of its collision with the boards, from largest to smallest (Use only A, B and C with"" orsymbols. Do not include any parentheses around the letters.) (b) If the puck's mass is 160 g, find the magnitude of the impulse applied by the boards in case A. kg m/s

Explanation / Answer

impulse = change in momentum

initially, v(x)= -3 m/s, taking positive value in +x direction

in A, v(x)= 1m/s,

in B, v(x)= 2 m/s

in C, v(x)= 3 m/s

so, change in velocity from initial velocity in increasing order is, A<B<C

so, corresponding magnitude of impulse , is A<B<C

(b) impulse by board in case A = m*1 - m *(-3)

= 4*m = 4*160/1000 kg.m/s

= 0.64 kg. m/s

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